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<blockquote data-quote="dredre04" data-source="post: 186034" data-attributes="member: 10759"><p>Hi,</p><p></p><p>the AWG 36 wire has a diameter of 0.005000 inches or 0.1270 millimeters. I will use the calculation in millimeters because it is the unit of measurement that I use geographically. Copper has a resistivity of 1,678 x10 ^ -8 ohms per meter so to obtain a total impedance of around 1000ohm you have to use about 750 meters of AWG36 wire for all 4 coils (185 meters each coil) and this could be the total wire that you used for your PI Coil</p><p></p><p>The AWG60 wire is 0.000309 inches in diameter or 0.00785 millimeters (frighteningly thin and unmanageable). If you use the AWG60 cable as shown in the video (I understand AWG60. You don't?) The length of the wire is very much less because the resistivity is inverse to the wire diameter then with more the wire is thin and with more the resistivity per meter is high. This wire has a resistivity of 1.3610219474721896 ohms per meter so to make a 1000ohms coil you really need 3 meters of this wire.</p><p></p><p>Since I really understand a thread 60 why did you use a different thread thickness? It is obvious that the coil must be much much larger because if the wire diameter increases. Below I put the links I used for the dimensions and the calculations.</p><p></p><p><a href="https://chemandy.com/calculators/round-wire-resistance-calculator.htm" target="_blank">Round Wire dc Resistance Calculator</a></p><p></p><p><a href="https://www.rembar.com/resources/american-wire-gauge-awg/" target="_blank">https://www.rembar.com/resources/american-wire-gauge-awg/</a></p><p></p><p>Finally I can't use a multimeter measure the impedance every now and then because the wire is insulated and in order not to cut it I should strip the insulation from time to time, which in a coil you should never do. For this reason, calculations are made on the diameter of the wire to develop the diameter and thickness of each winding. Also because here we have 4 separate wingdings that make the measurement even more complicated.</p></blockquote><p></p>
[QUOTE="dredre04, post: 186034, member: 10759"] Hi, the AWG 36 wire has a diameter of 0.005000 inches or 0.1270 millimeters. I will use the calculation in millimeters because it is the unit of measurement that I use geographically. Copper has a resistivity of 1,678 x10 ^ -8 ohms per meter so to obtain a total impedance of around 1000ohm you have to use about 750 meters of AWG36 wire for all 4 coils (185 meters each coil) and this could be the total wire that you used for your PI Coil The AWG60 wire is 0.000309 inches in diameter or 0.00785 millimeters (frighteningly thin and unmanageable). If you use the AWG60 cable as shown in the video (I understand AWG60. You don't?) The length of the wire is very much less because the resistivity is inverse to the wire diameter then with more the wire is thin and with more the resistivity per meter is high. This wire has a resistivity of 1.3610219474721896 ohms per meter so to make a 1000ohms coil you really need 3 meters of this wire. Since I really understand a thread 60 why did you use a different thread thickness? It is obvious that the coil must be much much larger because if the wire diameter increases. Below I put the links I used for the dimensions and the calculations. [URL="https://chemandy.com/calculators/round-wire-resistance-calculator.htm"]Round Wire dc Resistance Calculator[/URL] [URL]https://www.rembar.com/resources/american-wire-gauge-awg/[/URL] Finally I can't use a multimeter measure the impedance every now and then because the wire is insulated and in order not to cut it I should strip the insulation from time to time, which in a coil you should never do. For this reason, calculations are made on the diameter of the wire to develop the diameter and thickness of each winding. Also because here we have 4 separate wingdings that make the measurement even more complicated. [/QUOTE]
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