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<blockquote data-quote="nickrulercreator" data-source="post: 174992" data-attributes="member: 10256"><p>I'm assuming you're talking about the <a href="http://www.ghyzmo.com/energy-units/" target="_blank">total emitted power</a> of the sun, right? You do know that the Earth only receives about 1/2.2billionth of that? 3.86x10^26 * .0000000045 = 1.73*10^17 watts. But, Earth is REALLY big. It has a cross section of 127,400,000km^2, so it's about <a href="https://en.wikipedia.org/wiki/Solar_constant" target="_blank">1.36kW/m^2</a>, or 81.65kJ/m^2. Is this a lot? Well, we need to know if this is ionizing radiation (the harmful kind), what kind of radiation it is (particles, waves, etc), what was the intensity of the radiation when hitting the hull of the craft, and then we need to know how much of it can penetrate a .75inch (minimum) hull of aluminum.</p><p></p><p>Luckily, <a href="https://web.archive.org/web/20090428112627/http://lsda.jsc.nasa.gov:80/books/apollo/S2ch3.htm" target="_blank">seismometers</a> were carried on each mission. No mission got anywhere close to deadly amounts.</p><p></p><p>Also, I invite you to read these three pages on radiation, the Van Allen Belts, and Solar Particle Radiation:</p><p></p><p><a href="http://www.clavius.org/envradintro.html" target="_blank">Clavius: Environment - radiation primer</a></p><p><a href="http://www.clavius.org/envrad.html" target="_blank">Clavius: Environment - radiation and the van allen belts</a></p><p><a href="http://www.clavius.org/envsun.html" target="_blank">Clavius: Environment - here comes the sun</a></p></blockquote><p></p>
[QUOTE="nickrulercreator, post: 174992, member: 10256"] I'm assuming you're talking about the [URL='http://www.ghyzmo.com/energy-units/']total emitted power[/URL] of the sun, right? You do know that the Earth only receives about 1/2.2billionth of that? 3.86x10^26 * .0000000045 = 1.73*10^17 watts. But, Earth is REALLY big. It has a cross section of 127,400,000km^2, so it's about [URL='https://en.wikipedia.org/wiki/Solar_constant']1.36kW/m^2[/URL], or 81.65kJ/m^2. Is this a lot? Well, we need to know if this is ionizing radiation (the harmful kind), what kind of radiation it is (particles, waves, etc), what was the intensity of the radiation when hitting the hull of the craft, and then we need to know how much of it can penetrate a .75inch (minimum) hull of aluminum. Luckily, [URL='https://web.archive.org/web/20090428112627/http://lsda.jsc.nasa.gov:80/books/apollo/S2ch3.htm']seismometers[/URL] were carried on each mission. No mission got anywhere close to deadly amounts. Also, I invite you to read these three pages on radiation, the Van Allen Belts, and Solar Particle Radiation: [URL="http://www.clavius.org/envradintro.html"]Clavius: Environment - radiation primer[/URL] [URL="http://www.clavius.org/envrad.html"]Clavius: Environment - radiation and the van allen belts[/URL] [URL="http://www.clavius.org/envsun.html"]Clavius: Environment - here comes the sun[/URL] [/QUOTE]
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