The Eye of Ra resembles the human brain any connection? Sorry don't mean to steer the thread off topic.
198343820949598453 / 354895949028343891
= 0.558878797
(198343820949598453/planck's constant) = 2.99338573e50 m^-2 kg^-1 s
For a HARMONICA:
There are 20 vertical harmonic sections, which is separated in half, for a total of 40 harmonic sections.
A rainbow has 7 basic "stars" (ROYGBIV), with "up/down" fluctuations totaling for 280 sections in the harmonica.
Accounting for the ratio of the circle, "Tau", and the harmonic golden ratio, "Phi", the I-CHING book of changes hexagram giving the number "8^2=64", and the cubic/square ratio between these:
((tau/phi)^2*280^2 - 1/30)^(3/2) =
1.28543689e9
((tau/(64phi))^2*280^2 - 1/30)^(3/2)=
= 4902.70337
(((64*tau/phi))^2*280^2 - 1/30)^(3/2) + ((tau/(64*phi))^2*280^2 - 1/30)^(3/2))^(1/64) = 1.68652819
After 7, "ROYGBIV", comes 8, Lavender/Pink.
78 = 2*3*13
1.68652819*78 = (1.68652819 * 78) =
131.54919882
3: (red-yellow-red) = gold. 1+3+1 = 5 = blue.
gold+blue = aqua
8: (blue-green-magenta-red-magenta-lavender-lavender-orange)
with a mirror (8):
(blue-green-magenta-red-magenta-lavender-lavender-orange-orange-lavender-lavender-magenta-red-magenta-green-blue) = whole rainbow
5+4+9+1+9+8+8+2 = 46 = blue-indigo
4+6 = 10 = aqua
Harmonica is therefore a Silver-Aqua-Golden-Indigo Pipe/Flute. It's all in the music, colors, and numbers.
Next, for the rows, which are distributed like this:
+[1][2][3][4][5][6][7][8][9][10][11][12][13][14][15][16][17][18][19][20]
-i[1][2][3][4][5][6][7][8][9][10][11][12][13][14][15][16][17][18][19][20]
with 40 total,
e^(i*131.54919882/40) = e^(i*3.28872997)
e^(i*3.28872997) has an absolute value of 1.
The "half-measure" of this, for +1 would be:
abs(e^(i*131.54919882) + e^(i*131.54919882/40))
= 0.538116276 for 1, or RED.
02*0.538116276 = 1.07623255
03*0.538116276 = 1.61434883
04*0.538116276 = 2.15246510
05*0.538116276 = 2.69058138
10*0.538116276 = 5.38116276
15*0.538116276 = 8.07174414
20*0.538116276 = 10.7623255
25*0.538116276 = 13.4529069
30*0.538116276 = 16.1434883
35*0.538116276 = 18.8340697
40*0.538116276 = 21.5246510
This corresponds to the fibbonacci sequence:
1,1,2,3,5,8,13,21
Fibonacci number - Wikipedia, the free encyclopedia
Tarot - Wikipedia, the free encyclopedia
"The tarot (/ˈtæroʊ/; first known as trionfi and later as tarocchi, tarock, and others) is a pack of playing cards (most commonly numbering 78), used from the mid-15th century in various parts of Europe to play a group of card games such as Italian tarocchini and French tarot. From the late 18th century until the present time the tarot has also found use by mystics and occultists in efforts at divination or as a map of mental and spiritual pathways.
Like a normal deck of cards, the tarot has four suits (which vary by region, being the French suits in Northern Europe, the Latin suits in Southern Europe, and the German suits in Central Europe). Each of these suits has pip cards numbering from ace to ten and four face cards for a total of 14 cards. In addition, the tarot has a separate 21-card trump suit and a single card known as the Fool. Depending on the game, the Fool may act as the top trump or may be played to avoid following suit."
Namaste, relatives of The Rainbow Clan.
So then, what becomes of the frequency of these? Well, it depends on the pressure.
F=MA
The density of Air is 1.225 kg/m^3.
o = M/V
F=MA/V
F=oA
F/A=o=M
E=hf
f=E/h
E=MC^2
f=(MC^2)/h
f=(oC^2)/h
f=((1.225 kg/m^3)C^2)/h
f = 1.84875813e33 s^3 A^2 / m^5
now, because there are 40 subsections:
(1.84875813e33 s^3 A^2 / m^5)/40
= 4.62189533e31 s^3 A^2 / m^5
and (1) is "0.538116276"
this means that [1] would have an f of
0.538116276 * 4.62189533e31 s^3 A^2 / m^5
= 2.4871171e31 s^3 A^2 / m^5
these numbers are pretty high. this is just the relative sound density per point. the above number would be the sound density of "RED".
the logarithmic inverse sound density of [1, RED] would be
72.2912621.
2

violet-orange) = magenta. 7*2 = gray.
orange-magenta-red-orange-indigo-orange-red
however, because this measure is for a singular spectrum, and there are 40 measures, we divide
72.2912621/40 =
1.80728155
for [1] RED's numerical tone, and thus, "Energy" for the formula
E=hv
E=h(1.80728155((s^1/ (m^3 A^2))
= 1.19751733e-33 (kg / m)(1/A^2)
the natural logarithm for this measure would then be
ln(1.19751733e-33 (kg / m)(1/A^2))
(2A)75.8050575468.
(2)75.8050575468 in google strangely gives the result of the Laccadive Sea.
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