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<blockquote data-quote="TimeFlipper" data-source="post: 157318" data-attributes="member: 6456"><p>My friend, iam certain that you will agree with me that a radio wave is better known as an electromagnetic wave...So that sort of blows up your idea that a radio wave, according to you has no current and no magnetic field..The term Electric refers to either the Voltage or the Current..<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite38" alt=":)" title="Smile :)" loading="lazy" data-shortname=":)" /></p><p></p><p>Regarding the bulb or lamp, its still the current that is responsible for lighting it up, the voltage merely carries or pushes the current along <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite59" alt="(y)" title="Thumbs up (y)" loading="lazy" data-shortname="(y)" />.</p><p>The link you provided for me has nothing in it that mentions radio antennas...Power is measured in another of Ohm`s Laws...</p><p></p><p>P=power, expressed in watts or milliwatts or microwatts..I=is the current, expressed in amps or milliamps or microamps..V=voltage expressed in volts or millivolts of a volt..Thus P=IxV (and not P=VxI)..as you stated)...Therefore I=the current (amps).. (lets say 10amps) and V=the voltage (lets say 10volts)..multiply the 10amps by 10volts and we have 100watts of power....If we wish to discover the Current (amps), we divide the Power by the Voltage..Thus 100watts of Power divided by the Voltage of 10Volts equals 10Amps...And if we wish to discover the voltage, we divide the Power by the current..thus 100Watts of power divided by the current of 10Amps equals 10Volts..<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite38" alt=":)" title="Smile :)" loading="lazy" data-shortname=":)" /></p><p></p><p>Allow me to explain the magic of Radio Antenna`s...Lets say i want an antenna for the10Mhz amateur radio band that is very simple and requires no inductors or capacitors to tune it....I would select a half wave dipole that is "resonant" for 10Mhz...It would be a horizontal length of thick copper wire with a total length of 15 meters, cut in half....One half of the antenna would the transmitting/receiving side and the other half acting as ground...(or positive and negative referring to the transmitter output....</p><p></p><p>How will i get the length for a fully resonant half wave dipole antenna on that 10Mhz amateur radio frequency??....We know that the speed of light travels close to 300,000,000 meters per second...So we drop the zero`s down to this level, to come up with a simple equation, 10(mhz) divided into 300, becomes 10 divided into 300 which is 30meters for the length of a "full wave dipole", but we want a half wave dipole so we cut the 30meters length into half, which leaves us with 15meters of copper wire, which we cut in half, as above..</p><p></p><p>Maybe there is something in what i have told you that might be of interest to you when you are thinking about Scalar Wave Antennas, and im certain that the Prof [USER=13]@Opmmur[/USER] will tell you everything that i have told you is accurate about an AC (alternating current) going into a resonant antenna which creates an electro-magnetic wave (not an electric wave as you suggested) for every single radio transmitter that has..is..and always will be, an electro-magnetic wave thats derived from an AC current which comes out of every radio transmitter..<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite43" alt=":cool:" title="Cool :cool:" loading="lazy" data-shortname=":cool:" /></p><p>The actual distance a radio wave can travel depends firstly on the effectiveness of the antenna and the atmospheric changes in the ionosphere and troposphere...</p><p></p><p>[ATTACH=full]6405[/ATTACH] <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite39" alt=";)" title="Wink ;)" loading="lazy" data-shortname=";)" />..</p><p></p><p>And now we must get closer to the original topic for this thread <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite38" alt=":)" title="Smile :)" loading="lazy" data-shortname=":)" /></p></blockquote><p></p>
[QUOTE="TimeFlipper, post: 157318, member: 6456"] My friend, iam certain that you will agree with me that a radio wave is better known as an electromagnetic wave...So that sort of blows up your idea that a radio wave, according to you has no current and no magnetic field..The term Electric refers to either the Voltage or the Current..:) Regarding the bulb or lamp, its still the current that is responsible for lighting it up, the voltage merely carries or pushes the current along (y). The link you provided for me has nothing in it that mentions radio antennas...Power is measured in another of Ohm`s Laws... P=power, expressed in watts or milliwatts or microwatts..I=is the current, expressed in amps or milliamps or microamps..V=voltage expressed in volts or millivolts of a volt..Thus P=IxV (and not P=VxI)..as you stated)...Therefore I=the current (amps).. (lets say 10amps) and V=the voltage (lets say 10volts)..multiply the 10amps by 10volts and we have 100watts of power....If we wish to discover the Current (amps), we divide the Power by the Voltage..Thus 100watts of Power divided by the Voltage of 10Volts equals 10Amps...And if we wish to discover the voltage, we divide the Power by the current..thus 100Watts of power divided by the current of 10Amps equals 10Volts..:) Allow me to explain the magic of Radio Antenna`s...Lets say i want an antenna for the10Mhz amateur radio band that is very simple and requires no inductors or capacitors to tune it....I would select a half wave dipole that is "resonant" for 10Mhz...It would be a horizontal length of thick copper wire with a total length of 15 meters, cut in half....One half of the antenna would the transmitting/receiving side and the other half acting as ground...(or positive and negative referring to the transmitter output.... How will i get the length for a fully resonant half wave dipole antenna on that 10Mhz amateur radio frequency??....We know that the speed of light travels close to 300,000,000 meters per second...So we drop the zero`s down to this level, to come up with a simple equation, 10(mhz) divided into 300, becomes 10 divided into 300 which is 30meters for the length of a "full wave dipole", but we want a half wave dipole so we cut the 30meters length into half, which leaves us with 15meters of copper wire, which we cut in half, as above.. Maybe there is something in what i have told you that might be of interest to you when you are thinking about Scalar Wave Antennas, and im certain that the Prof [USER=13]@Opmmur[/USER] will tell you everything that i have told you is accurate about an AC (alternating current) going into a resonant antenna which creates an electro-magnetic wave (not an electric wave as you suggested) for every single radio transmitter that has..is..and always will be, an electro-magnetic wave thats derived from an AC current which comes out of every radio transmitter..:cool: The actual distance a radio wave can travel depends firstly on the effectiveness of the antenna and the atmospheric changes in the ionosphere and troposphere... [ATTACH=full]6405[/ATTACH] ;).. And now we must get closer to the original topic for this thread :) [/QUOTE]
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